Date: Mon, 11 Jul 2005 18:25:40 +0530
Reply-To: Bhujle Vijay CE IN <vijay.bhujle**At_Symbol_Here**CIBASC.COM>
Sender: DCHAS-L Discussion List <DCHAS-L**At_Symbol_Here**LIST.UVM.EDU>
From: Bhujle Vijay CE IN <vijay.bhujle**At_Symbol_Here**CIBASC.COM>
Subject: Re: DCHAS-L Digest - 9 Jul 2005 to 10 Jul 2005 (#2005-80)
Comments: To: Labsafe**At_Symbol_Here**AOL.COM

As I get it the anh.HF cylinder has liquified gas.Hence the HF will be in liquified form and one should not take this as gaseous form to start with. Whatever the reaction takes place will give out Hydrogen in gaseous form and hence will lead to pressure build up. Regards Vijay bhujle -----Original Message----- From: DCHAS-L Discussion List [mailto:DCHAS-L**At_Symbol_Here**LIST.UVM.EDU] On Behalf Of Jim Kaufman Sent: Monday, July 11, 2005 4:53 PM To: DCHAS-L**At_Symbol_Here**LIST.UVM.EDU Subject: Re: [DCHAS-L] DCHAS-L Digest - 9 Jul 2005 to 10 Jul 2005 (#2005-80) In a message dated 7/11/2005 12:02:39 AM Eastern Daylight Time, LISTSERV**At_Symbol_Here**LIST.UVM.EDU writes: > 6HF + 2Fe yields 2FeF3 + 3H2 2HF + Fe = FeF2 + H2 It does not matter whether it forms FeF3 or FeF2. In either case there will be fewer gas molecules in the cylinder and the pressure will go down and not up. Therefore, I agree with Jay (although it pains me to no extent ), that the tank ruptured because of the wall thinning. James A. Kaufman, Ph.D. President/CEO jimkaufman**At_Symbol_Here** The Laboratory Safety Institute A Nonprofit International Organization for Safety in Science and Science Education 192 Worcester Road, Natick, MA 01760-2252 508-647-1900 Fax: 508-647-0062 Cell: 508-574-6264 Res: 781-237-1335 info**At_Symbol_Here**

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